Discriminants and the Hodge index on a real divisor space #
Macrì--Schmidt (arXiv:1607.01262v3, Definition 6.12) attach three quadratic quantities to a class on a polarised surface:
- the discriminant
Δ = (ch₁)² - 2 ch₀ ch₂, which is invariant under everyB-twist; Δ^C_{ω,B} = Δ + C (ω · ch₁^B)², the support form of Theorem 6.13;\bar Δ^B_ω = (ω · ch₁^B)² - 2 ω² ch₀^B ch₂^B, the form that gives the support property on the(α,β)-plane.
Before this file the only discriminant available was the compressed one of
the (s,t) branch of the wall hierarchy. Here the three forms are defined on the
intrinsic ChernCharacter over an arbitrary real divisor space, and the
relations between them are proved:
discriminant_twist:Δdoes not seeB;omega_square_mul_discriminant_le_barDiscriminant:ω² Δ ≤ \bar Δ^B_ωwhenever the Hodge index inequality holds atω;barDiscriminant_rankOne: onB = βH,ω = αHthe bar form isα²times the compressed discriminant, independently ofβ, and through aNumericalRealizationthis isα² · discrH, henceα²times the wall-plane discriminant of the transported class.
The Hodge index input #
LinearAlgebra/BilinearForm/HodgeIndex.lean owns the proposition-valued Hodge
index and definiteness certificates. This module consumes that neutral input
for discriminants and orthogonal charge slices. Nothing here proves the
certificate for a geometric surface.
- a Hodge index on a realized divisor space yields the numerical
HodgeIndexStatementofBogomolovGieseker.lean, which is the same inequality restricted to first Chern classes of numerical classes; - the numerical statement yields the inequality on realized first Chern
classes only. It does not yield
DivisorSpace.HodgeIndex, because it quantifies over classesE : Nand not over arbitrary real divisors. The two certificates are therefore related in one direction only, and that asymmetry is the honest content of this file, not an omission.
For orthogonal slices, OrthogonalSlice.isHodge_of_hodgeIndex derives the
IsHodge certificate from the Hodge index inequality plus nondegeneracy of the
transverse pairing; the inequality alone gives only ≤ 0 on H^⊥, which is
OrthogonalSlice.transverse_square_nonpos_of_hodgeIndex. Conversely
IsHodge.index_le_B recovers the inequality on the B-fields a slice can
reach. The rank-one slice is Hodge as soon as H² > 0.
What is not here #
No Bogomolov inequality is proved. discriminant_nonneg_of_semistable and its
consequences take BogomolovGiesekerData, the supplied datum of
BogomolovGieseker.lean, and transport it; the statement
0 ≤ \bar Δ^B_ω(E) for a semistable E and arbitrary (B, ω) is obtained only
under a supplied Hodge index at ω.
Orthogonal slices #
The Hodge index inequality gives nonpositive square on every transverse direction.
Hodge index plus nondegeneracy of the transverse pairing gives the
IsHodge certificate. Nondegeneracy is stated as: a nonzero transverse
parameter has nonzero square; it implies injectivity of transverse.
The pairing of H with the B-field of a slice point sees only the
longitudinal coefficient.
On the B-fields of a Hodge slice the index inequality holds outright:
this is the direction from IsHodge back to the inequality, on the classes the
slice can reach.
The rank-one slice is Hodge as soon as H² > 0: there are no transverse
directions.
The three discriminants #
The discriminant Δ(E) = (ch₁)² - 2 ch₀ ch₂, with (ch₁)² computed by
the intersection form of the divisor space.
Instances For
The divisorial discriminant is the Mukai self-pairing of the
Chern-character triple, at coefficient ring ℝ and the divisor space's own
intersection form.
This is the leaf that fixes the arity: the middle summand here is D, an
arbitrary real divisor space, not a copy of ℝ. The root generalises over the
coefficient ring for the sake of the ℚ- and A-valued leaves, never over the
number of slots.
The discriminant is invariant under every B-twist: Δ(ch^B) = Δ(ch).
The ω-bar discriminant \bar Δ^B_ω(E) = (ω · ch₁^B)² - 2 ω² ch₀^B ch₂^B
of Macrì--Schmidt Definition 6.12.
Equations
Instances For
The C-discriminant Δ^C_{ω,B}(E) = Δ(E) + C (ω · ch₁^B)² of
Macrì--Schmidt Definition 6.12; the constant C is the one of their
Exercise 6.11 and is supplied by the caller.
Equations
Instances For
For C ≥ 0 the C-discriminant dominates the discriminant.
ω² Δ ≤ \bar Δ^B_ω under the Hodge index inequality at ω. This is
the step by which Macrì--Schmidt pass from Bogomolov's Δ ≥ 0 to the support
form on the (α,β)-plane.
A nonnegative discriminant gives a nonnegative bar discriminant at every
(B, ω) with the Hodge index inequality at ω.
The compressed discriminant and the rank-one slice #
The compressed discriminant (∫H·ch₁)² - 2 (∫H²) ch₀ ∫ch₂ on charge
coordinates: the shape consumed by the wall-plane
Wall.NumClass.discr, with the rank slot weighted by ∫H².
Instances For
The compressed discriminant is the Mukai self-pairing with the rank slot carrying the polarisation square.
The triple is (∫H²·rk, ∫H·ch₁, ∫ch₂), not (rk, ∫H·ch₁, ∫ch₂). The ∫H²
weight is what makes this the same quantity as the uncompressed
ChernCharacter.discriminant on the rank-one slice, and dropping it is the
error the surface transport's docstring already warns about.
The integral bridge: on the rank-one slice the compressed discriminant is
∫H² times the uncompressed one.
Δ_H(E) = (∫H²) · Δ(E) whenever c₁(E) is a multiple of H, which is exactly
the hypothesis hc. Both sides are Mukai.selfPairing of the same root — the
left at the compressed triple, the right at the divisorial one — so the whole
content is where the weight goes.
The weight cannot be normalised away. The two agree on the nose only when
∫H² = 1; at any other polarisation degree they differ by that factor, and
reading the compressed discriminant as the uncompressed one is the error
Numerical/Stability/WallTransport.lean records having made once. The
statement is confined to the rank-one slice by necessity: off it, c₁ has
components orthogonal to H that the compression discards, so no factor
relates the two.
The companion statement on the pairings rather than the discriminants belongs
to the bridge epic beside Mukai.realPairing; this is the discriminant-level
form, and that one should be stated against it rather than re-derived.
On the rank-one slice B = βH, ω = αH the bar discriminant is α²
times the compressed discriminant at H, and does not depend on β.